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the correlation coefficient r between a child age x and the number of minutes spent doing homework each day y is 0.694.

What percent of the variation?

A. 30.6%
B. 48.2%
C. 51.8%
D. 69.4%

Respuesta :

MissPhiladelphia
The final answer to your question is that the percent variation of  the correlation coefficient between a child age x and the number of minutes spent doing homework each day y with r = 0.694 is C. 51.8%.
Hope my answer would be a great help for you.

Answer:

The answer is 48.2%

Step-by-step explanation:

The correlation coefficient r between a child age x and the number of minutes spent doing homework each day y is 0.694 i.e r=0.694

Now, we have to find percent of the variation.

The coefficient of determination is [tex]r^{2}[/tex]

The square of r(correlation coefficient) is the percent of variation that is explained by the dependent variable.

If r=0.694 ⇒[tex]r^{2}= (0.694)^{2}=0.482[/tex] this means that 48.2% of variation in dependent variable.


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