Respuesta :

We have the following values used to solve this:
For ⁴₂He:
No of protons: 2
No of neutrons : 2
Mass of proton: 1.00728 amu
Mass of neutron: 
1.00867 amu
Atomic mass: 
4.002603 amu

The formula to solve for the mass defect is:
md = (mp + mn) - mo
md = (2x
1.00728 + 2x1.00867) - 4.002603
md = 0.029297

Therefore, the mass defect is 0.029297 amu

The mass defect of the helium nucleus ⁴He₂ is 0.030377 u

Further explanation

Mass defect means the difference between the mass of particles forming an atom with an atomic mass.

[tex]\large {\boxed {\Delta m = [ Z ( m_p + m_e) + (A - Z)m_n ] - M} }[/tex]

Δm = mass defect ( u )

mp = mass of proton ( u )

me = mass of electron ( u )

mn = mass of neutron ( u )

M = atomic mass ( u )

A = mass number

Z = atomic number

Let us now tackle the problem !

Given :

[tex]\text{mass of proton} = m_p = 1.00728 ~ u[/tex]

[tex]\text{mass of electron} = m_e = 0.00055 ~ u[/tex]

[tex]\text{mass of neutron} = m_n = 1.00866 ~ u[/tex]

[tex]\text{atomic mass} = M = 4.002603 ~ u[/tex]

[tex]\text{atomic number} = Z = 2[/tex]

[tex]\text{mass number} = A = 4[/tex]

Unknown :

Δm = ?

Solution :

[tex]\Delta m = [ Z ( m_p + m_e) + (A - Z)m_n ] - M[/tex]

[tex]\Delta m = [ 2 ( 1.00728 + 0.00055 ) + ( 4 - 2 )( 1.00866 ) ] - 4.002603[/tex]

[tex]\Delta m = [ 2.01566 + 2.01732 ] - 4.002603[/tex]

[tex]\Delta m = 4.03298 - 4.002603[/tex]

[tex]\boxed {\Delta m = 0.030377 ~ u}[/tex]

Learn more

  • Rutherford’s major achievements : https://brainly.com/question/1552732
  • Unit of radius of an atom : https://brainly.com/question/1968819
  • Fusion : https://brainly.com/question/11395223

Answer details

Grade: College

Subject: Physics

Chapter: Nuclear Physics

Keywords: Mass , Defect , Nucleon , Number , Atomic , Proton , Electron , Neutron

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