Can someone please help me!

Answer: Pretty sure that it's y=-5/3x+8
Step-by-step explanation: Since the slope-intercept form is y=mx+b with b as the y-intercept and m as the slope. b would be 8 since that's where the line intercepts the y-axis and the slope is -5/3 (negative bc the line is slanted down)
Answer:
y = - [tex]\frac{8}{5}[/tex] x + 8
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Calculate the slope m using the slope formula
m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]
with (x₁, y₁ ) = (0, 8) and (x₂, y₂ ) = (5, 0 ) ← 2 points on the line
m = [tex]\frac{0-8}{5-0}[/tex] = [tex]\frac{-8}{5}[/tex] = - [tex]\frac{8}{5}[/tex]
The line crosses the y- axis at (0, 8 ) ⇒ c = 8
y = - [tex]\frac{8}{5}[/tex] x + 8 ← equation of line