Respuesta :
Answer: F
Step-by-step explanation:
A square is always positive:
[tex](x-3)^2 \geq 0\\\\g(x)=(x-3)^2+1 \geq 1\\\\answer\ F\\[/tex]
Answer:
F.
Step-by-step explanation:
The expression (x - 3)^2 is always >= 0.
The minimum value of g occurs when x = 3 :- that is (3-3)^2 + 1 = 1.
The range of g(x) is all real numbers >= 1.