A bacteria culture doubles every 5 hours. Determine the hourly growth rate of the bacteria
culture. Round your answer to the nearest tenth of a percent.

Respuesta :

Answer:

10

Step-by-step explanation:

Using an exponential function, it is found that the hourly growth rate of the bacteria culture is of 14.9%.

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An exponential function has the following format:

[tex]A(t) = A(0)(1+r)^t[/tex]

In which:

  • A(0) is the initial amount.
  • r is the hourly growth rate.

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Since it doubles every 5 hours, it means that:

[tex]A(5) = 2A(0)[/tex]

And we use this to find r.

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[tex]A(t) = A(0)(1+r)^t[/tex]

[tex]2A(0) = A(0)(1+r)^5[/tex]

[tex](1 + r)^5 = 2[/tex]

[tex]\sqrt[5]{(1 + r)^5} = \sqrt[5]{2}[/tex]

[tex]1 + r = 2^{\frac{1}{5}}[/tex]

[tex]1 + r = 1.149[/tex]

[tex]r = 1.149 - 1 = 0.149[/tex]

0.149*100% = 14.9%.

The hourly growth rate of the bacteria culture is of 14.9%.

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