The percentage change of pH for the water is 56%.
In this exercise, you're required to calculate the percent change of pH for water from an experiment by using the necessary parameters (values).
In Chemistry, pH literally means the power of hydrogen ions and it's a measure of the molar concentration of hydrogen ions in a particular solution, thus, specifying the;
- Acidity of a chemical solution.
- Neutrality of a chemical solution.
- Basicity (Alkanility) of a chemical solution.
A pH scale measures the concentration of hydrogen ions in acidic and alkaline solutions. Typically, the pH scale is calibrated with a standard measurement that ranges from 0 to 14.
Note: The required parameters are missing from the question. Thus, let's assume some values to illustrate how to solve the question.
Assumed data:
pH at 0 drops = 2.5
pH at 5 drops = 1.1
Mathematically, the percentage change of pH would be calculated by using this formula;
[tex]Percent \;Change \;of \;pH = \frac {pH \;at \;5 \;drops\; - \;pH \;at \;0 \;drops}{pH \;at \;0 \;drops}[/tex] × [tex]100[/tex]
Substituting the values into the formula, we have;
[tex]Percent \;Change \;of \;pH = \frac {1.1 \;- \;2.5}{2.5}[/tex] × [tex]100[/tex]
Note: The negative sign must always be neglected when solving for percentage change.
[tex]Percent \;Change \;of \;pH = \frac {1.4}{2.5}[/tex] × [tex]100[/tex]
[tex]Percent \;Change \;of \;pH = 0.56[/tex] × [tex]100[/tex]
Percentage change of pH = 56%
Therefore, the percentage change of pH for the water is 56%.
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