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Find the height of the triangle by applying formulas for the area of a triangle and
your knowledge about triangles.

A. 5.8 mm
B. 2.0 mm
OC. 4.4 mm
D. 6.2 mm

Find the height of the triangle by applying formulas for the area of a triangle and your knowledge about triangles A 58 mm B 20 mm OC 44 mm D 62 mm class=

Respuesta :

devishri1977

Answer:

Step-by-step explanation:

a= 12 mm ; b = 16 mm  ; c = 18 mm

s = (a + b+c)/2

[tex]=\dfrac{12 + 16 + 8}{2}\\\\= \dfrac{36}{2}\\\\= 18\\\\[/tex]

s -a =  18 -  12 = 6 mm

s  -b = 18 - 16 = 2 mm

s  -c = 18 - 8 = 10 mm

[tex]area = \sqrt{s(s -a)(s-b)(s-c)}[/tex]

       [tex]= \sqrt{18*6*2*10}\\\\= \sqrt{2160 }\\\\=46.47\\\\=46 \ mm^{2}\\[/tex]

[tex]\dfrac{1}{2}* \ base * \ height = 46\\\\\dfrac{1}{2}*16* \ height = 46\\\\height = \dfrac{46*2}{16}\\\\[/tex]

  = 5.75

Height = 5.8 mm

AnishAdhikari

Answer:

A. 5.8mm

Step-by-step explanation:

[tex]area \: of \: triangle = \sqrt{s(s - a) \times (s - b) \times (s - c)} \\ s = \frac{a + b + c}{2} \\ s = \frac{12 + 8 + 16}{2} \\ s = 18 \\ area \: of \: triangle \: = \sqrt{18(18 - 12) \times (18 - 8) \times (18 - 16)} \\ = \sqrt{2160} \\ = 46.47 {m}^{2} \\ area \: of \: triangle \: = \frac{1}{2} \times base \times height \\ 46.47 = \frac{1}{2} \times 16 \times h \\ h = \frac{46.47}{8} \\ h = 5.8mm[/tex]

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