Respuesta :
The probability that no two teams win the same number of games, P ≈ 2.084 × 10⁻⁴⁵³
The reason for arriving at the above probability is as follows:
The given parameters are;
The number of teams in the tournament, n = 60
The chance of a team winning a game = 50% = 0.5
The number of ties = No ties
The required parameter:
The probability that no two teams win the same number of games
Method:
Calculate the number of ways no two teams win the same number of games, and divide the result by the total number of possible outcomes
Solution:
The number of matches played, n = [tex]\dbinom {60} {2}[/tex] = 1,770
The possible outcomes = 2; Winning or losing
The total number of possible outcomes, [tex]n_p[/tex] = 2¹⁷⁷⁰
The number of games won by each team is between 0 and 59
The ways in which no two teams won the same number of games is given by the games won by the teams to be 0, 1, 2,..., 57, 58, 59
Therefore, the number of ways no two teams won the same number of games, the required outcomes, [tex]n_k[/tex] = 59!
[tex]Probability = \dfrac{Number \ of \ possible \ outcomes}{Number \ of \ required\ outcomes}[/tex]
The probability that no two teams win the same number of games is given as follows;
[tex]\mathbf{P(No \ two \ teams \ won \ the \ same \ number \ of \ games)} = \dfrac{n_k}{n_p}[/tex]
Therefore;
[tex]P(No \ two \ teams \ won \ the \ same \ number \ of \ games) = \dfrac{59!}{2^{1,770}} \approx \mathbf{2.084 \times 10^{-453}}[/tex]
The probability that no two teams win the same number of games, P ≈ 2.084 × 10⁻⁴⁵³
Learn more about probability theory here:
https://brainly.com/question/1539712
