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If a point has 40 J of energy and the electric potential is 8 V, the charge must be: A. 5 C

Given the following the details;

  • Energy = 40 Joules
  • Electric potential = 8 Volts

To find the quantity of charge;

Mathematically, the quantity of charge with respect to electric potential is given by the formula;

[tex]Quantity \; of \; charge = \frac{Energy}{Electric \; potential}[/tex]

Substituting the values into the formula, we have;

[tex]Quantity \; of \; charge = \frac{40}{8}[/tex]

Quantity of charge = 5 Coulombs

Therefore, the quantity of charge must be 5 Coulombs.

Find more information: https://brainly.com/question/21808222
  • Energy=E=40J
  • Potential difference=V=8V
  • Charge=Q

[tex]\boxed{\sf E=QV}[/tex]

[tex]\\ \rm\longmapsto Q=\dfrac{E}{V}[/tex]

[tex]\\ \rm\longmapsto Q=\dfrac{40}{8}[/tex]

[tex]\\ \rm\longmapsto Q=5C[/tex]

Hence total charge must be 5C.

Note:-

SI unit of charge is Coulomb (C)

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