Respuesta :
Let the amount paid for a a primary child be x and that of a toddler be y, then
22x + 18y = 24250 . . . (1)
30x + 15y = 27150 . . . (2)
solving the simultaneous linear equations gives that x = 595 and y = 620
Therefore, parents pay $595 for a primary child and $620 for a toddler child.
22x + 18y = 24250 . . . (1)
30x + 15y = 27150 . . . (2)
solving the simultaneous linear equations gives that x = 595 and y = 620
Therefore, parents pay $595 for a primary child and $620 for a toddler child.
Answer:
Parents pay for primary childrens be $595 and parents pay for toddler childrens be $ 620 .
Option (A) is correct .
Step-by-step explanation:
Let us assume that the parents pay for primary childrens be x .
Let us assume that the parents pay for toddler childrens be y .
As given
.One location of The Smart Growing Preschool has 22 children in the primary class and 18 children in the toddler class.
The revenue at the first location is $24,250 .
Than the equation becomes
22x + 18y = 24250
As given
The other location has 30 children in the primary class and 15 children in the toddler class.
The revenue at the second location is $27150.
Than the equation becomes
30x + 15y = 27150
Than two equations are
22x + 18y = 24250
30x + 15y = 27150
Multiply 22x + 18y = 24250 by 15 .
15 × (22x + 18y = 24250)
15 × 22x + 15 × 18y = 15 × 24250
330x + 270y = 363750
Multiply 30x + 15y = 27150 by 18 .
18 × ( 30x + 15y = 27150 )
18 × 30x + 18 × 15y = 18 × 27150
540x + 270y = 488700
Now subtracted 330x + 270y = 363750 from 540x + 270y = 488700 .
540x - 330x + 270y - 270y = 488700 - 363750
210x = 124950
[tex]x = \frac{124950}{210}[/tex]
x = $ 595
Putting in the equation
22x + 18y = 24250
22 × 595 + 18y = 24250
13090 + 18y = 24250
18y = 24250 - 13090
18y = 11160
[tex]y = \frac{11160}{18}[/tex]
y = $ 620
Therefore the parents pay for primary childrens be $595 and parents pay for toddler childrens be $ 620 .
Option (A) is correct .