Answer:
A. One solution
Step-by-step explanation:
Given quadratic equation is,
[tex]8x^2+8x+2=0[/tex]
Since, if for a quadratic equation [tex]ax^2+bx+c[/tex],
The discriminant,
[tex]D=b^2-4ac > 0[/tex]
The equation has two real different solutions,
If D = 0,
The equation has one real solution with multiplicity two,
While, if D < 0,
The equation has two imaginary solutions,
Here, the discriminant,
[tex]D=(8)^2-4\times 8\times 2=64-64 = 0[/tex]
Thus, by the above explanation,
It is clear that the given equation has one real solution,
Option A is correct.
