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which of the following atoms is least likely to form chemical bonds with other atoms

a. a hydrogen containing 1 valence electron
b. a carbon atom containing 4 valence electrons
c. a neon containing 4 valence electrons
d. a sodium atom containing 1 valence electron

Respuesta :

mpanderla95
The atom that would least likely form chemical bonds with other atoms would be C. A neon containing 4 valence electrons, this is because neon itself is an inert gas, it would not necessarily react as it already possess the maximum number of electrons needed to achieve stability and have a full octet, even if it is forced to obtain 4 valence electrons it would not react with other atoms.
aachen

An atom is likely to form a bond with other atoms when it is achieving to complete its octet or duplet in the valance shell.

  • The hydrogen atom containing one valence electron will form a bond with another atom in order to achieve two electrons in its valance shell and become stable.
  • A carbon will form a covalent bond with other atoms to achieve its octet.
  • The sodium atom having one valence electron will also aim for stability by forming bonds.
  • Neon is an inert gas, and thus already has stability. It is least likely to react with other atoms in order to form bonds.

Thus, neon is the least likely among the given atoms to react with another atom. Hence, the correct answer is option c.

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