Answer:
Step-by-step explanation:
you are being asked to "Solve a quadratic"
There are various METHODS to do this.
You will learn a few of them
-graphing
-substation
-complete the square
-quadratic formula
in this case the question wants you to solve it using the
Quadratic formula...
Ax^2 + Bx + C = 0 is the quadratic.
your A=-1 B=14, and C=61
you just have to plug in those numbers into:
[tex]-B[/tex] ± [tex]\sqrt{\frac{B^{2}-4AC}{2A}}[/tex]
-14 ± [tex]\sqrt{\frac{14^{2}-4(-1)(61)}{2(-1)}}[/tex]
you should end up with 7+[tex]\sqrt{110}[/tex] & 7-[tex]\sqrt{110}[/tex]
which is -3.49 or 17.49
-3.49 does not make any sense, the 17.49 distance only makes sense for this problem
