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A hospital uses cobalt-60 in its radiotherapy treatments for cancer patients. Cobalt-60 has a half-life of 7
years. The hospital has 228 g of cobalt-60. Calculate the amount of colbalt-60 remaining after 18 months.
Round to two decimal places.

Respuesta :

whitneytr12

Answer:

We have 197 g of Co-60 after 18 months.

Step-by-step explanation:

We can use the decay equation.

[tex]M_{f}=M_{i}e^{-\lambda t}[/tex]

Where:

  • M(f) and M(i) are the final and initial mass respectively
  • λ is the decay constant (ln(2)/t(1/2))
  • t(1/2) is the half-life of Co
  • t is the time at the final amount of m

[tex]M_{f}=228e^{-\frac{ln(2)}{7} 1.5}[/tex]    

[tex]M_{f}=197\: g[/tex]    

Therefore, we have 197 g of Co-60 after 18 months.

I hope it helps you!

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