(2x-3)(x-4)(3x-1)
How do u get the 35x2 and 47x?

Answer: 6x^3-35x^2+47x-12
Step-by-step explanation:
(2x-3)(x-4)(3x-1)
=(2x^2-11x+12)(3x-1)
=6x^3-35x^2+47x-12