The given relation {(2,1), (4,2) (6,3) (8,4)} is one to many relation.
The other solution for this problem is given below.
The pattern is the sum of the two numbers plus the previous sum, i.e.
12 = 2+5 +(5)
21 = 3+6+ (12)
40 = 8+11 +21
These type of questions are part of reasoning and comes in random competitive exams which have multiple choice questions and therefore you have more than you want.
First , you need to multiply both numbers and then add the first number.
Therefore, 1+4= 1x4+1=5
2+5=2×5+2=12
3+6=3×6+3=21
A many-to-one relationship is where one entity (typically a column or set of columns) contains values that refer to another entity (a column or set of columns) that has unique values.
Hence,8+11=8×11+8=96
The other solution for this problem is given below.
The Solution for this is
1+4=5
1(4+1)=1(5)=5
2+5=12
2(5+1)=2(6)=12
3+6=21
3(6+1)=3(7)=21
Therefore we get,
8+11=8(11+1)=8(12)=96.
Therefore the given relation is any one to many relation.
To learn more about the relation visit:
https://brainly.com/question/1579288