This ellipse is centered at the
origin. Find its equation.
Vertices: (0,-6) and (0,6)
Foci: (0,-2) and (0,2)
y?
X^2/[?] + y^2/[?] =1

This ellipse is centered at the origin Find its equation Vertices 06 and 06 Foci 02 and 02 y X2 y2 1 class=

Respuesta :

Answer:

Equation of Ellipse is [tex]\frac{x^{2} }{32} +\frac{y^{2} }{36} =1[/tex]

Step-by-step explanation:

Let's find the value for [tex]a^{2}[/tex] and [tex]b^{2}[/tex] to write the equation for vertical ellipse.

Here 'a'  is the distance from center to one of the vertices.

"b" is the distance from center to one of the Co-vertices. We need to find this using formula [tex]a^{2} -b^{2} =c^{2}[/tex]

'c' is the distance between center to one of the Foci.

In this problem center is origin.

So, a =6(because distance between(0,0) and (0,6) is 6)

c= 2 (because distance between (0,0) and (0,2) is 2)

Plug in the known values into the formula [tex]a^{2} -b^{2} =c^{2}[/tex]

36-[tex]b^{2}[/tex]= 4

Subtract both sides 36

[tex]-b^{2}[/tex] = -32

Divide both sides by -1

[tex]b^{2}[/tex] =32

So, equation would be

[tex]\frac{x^{2} }{32} +\frac{y^{2} }{36} =1[/tex]