Answer:
[tex]d=2.7m[/tex]
Explanation:
From the question we are told that:
Electric Field strength [tex]E=8.53 * 10^3 V/m[/tex]
Potential difference is [tex]V= 23.0 kV[/tex]
Generally the equation for distance is mathematically given by
[tex]d=\frac{V}{E}[/tex]
[tex]d=\frac{23.0*10^3}{8.53 * 10^3 V/m}[/tex]
[tex]d=2.7m[/tex]
