Answer:
[tex]E=4.35\times 10^{-18}\ J[/tex]
Explanation:
Given that,
The distance between the electron and proton, [tex]r=5.29\times 10^{-11}\ m[/tex]
We need to find the change in electric potential energy. It can be calculated as follows :
[tex]E=\dfrac{kq_1q_2}{r^2}[/tex]
Where
k is the electrostatic constant
Change,
[tex]\Delta E=\dfrac{kq_1q_2}{r}-0[/tex]
Put all the values.
[tex]\Delta E=\dfrac{9\times 10^9\times (-1.6\times 10^{-19})^2}{5.29\times 10^{-11}}\\\\=-4.35\times 10^{-18}\ J[/tex]
So, the required change in electric potential energy is [tex]4.35\times 10^{-18}\ J[/tex].
