Help plz help needed i need the answer

Answer:
x = ±sqrt(26)
Step-by-step explanation:
ln ( x^2 -25) = 0
Raise each side to base e
e^ln ( x^2 -25) = e^0
x^2 -25 = 1
Add 25 to each side
x^2 -25 +25 = 1+25
x^2 = 26
Take the square root of each side
sqrt(x^2) = ±sqrt(26)
x = ±sqrt(26)
Answer:
The third option
Step-by-step explanation:
If we rewrite this in log form, we get
[tex]e {}^{0} = {x}^{2} - 25[/tex]
Remeber anything to the 0 power is 1, so simplifying the equation first
[tex]1 = {x}^{2} - 25[/tex]
Add 25 to both sides
[tex]26 = {x}^{2} [/tex]
Take the square root of both sides
[tex]x = \sqrt{26} [/tex]
Square root are both so
[tex]x = - \sqrt{26} [/tex]
Is also a answer.
The third option is the answer