Answer:
[tex]t=82.2s[/tex]
Explanation:
From the question we are told that:
Half life [tex]t_{1/2}=54.3s[/tex]
Change in concentration [tex]\triangle conc=6.50 M to 2.27 M[/tex]
Generally the equation for half life is mathematically given by
[tex]k=\frac{2.303}{t}*log\frac{C_1}{C_2}[/tex]
Where
[tex]K=\frac{0.693}{t_{1/2}}[/tex]
[tex]K=\frac{0.693}{54.3}[/tex]
[tex]K=0.0128[/tex]
Therefore
[tex]0.0128=\frac{2.303}{t}*log\frac{6.50}{2.27}[/tex]
[tex]t=82.2s[/tex]
