A car travelling at v kilometers per hour will need a stopping distance, d, in meters without skidding that can be modelled by the function d=0.0067v2+0.15v. Determine the speed at which a car can be travelling to be able to stop within 37m.

I’m need of serious help!

Respuesta :

Answer:

v =  14 km/h

Step-by-step explanation:

d = 0.0067[tex]v^{2}[/tex] + 0.15v

differentiate the function with respect to v to have;

d = 0.0134v - 0.15

given that the distance without skidding = 37 m (0.037 km) , then;

0.037 = 0.0134v - 0.15

0.0134v = 0.037 + 0.15

             = 0.187

v = [tex]\frac{0.187}{0.0134}[/tex]

  = 13.9552

v =  14 km/h

The speed of the car travelling would be 14 km/h to be able to stop within 37m.