Answer:
0.6 = 60% probability that he or she studies on a weeknight.
Step-by-step explanation:
We solve this question treating these events as Venn probabilities.
I am going to say that:
Probability A: Probability of a student studying on weeknights.
Probability B: Probability of a student studying on weekends.
Forty-two percent of students said they study on weeknights and weekends
This means that [tex]P(A \cap B) = 0.42[/tex]
47% said they studied on weekends
This means that [tex]P(B) = 0.47[/tex]
65% said they study either on weeknights or weekends.
This is [tex]P(A \cup B) = 0.65[/tex]
If you were to pick one student at random, what is the probability that he or she studies on a weeknight?
This is P(A), and the equation used is:
[tex]P(A \cup B) = P(A) + P(B) - P(A \cap B)[/tex]
Considering the values we have:
[tex]0.65 = P(A) + 0.47 - 0.42[/tex]
[tex]0.05 + P(A) = 0.65[/tex]
[tex]P(A) = 0.6[/tex]
0.6 = 60% probability that he or she studies on a weeknight.
Answer: 60% joaobezerra Is Right, and Confirmed by Buzz (Acceleration Education)
Step-by-step explanation:
We solve this question by treating these events as Venn probabilities. Forty-two percent of students said they study on weeknights and weekends. This means that 47% said they studied on weekends. This means that 65% said they study either on weeknights or weekends. This is If you were to pick one student at random, what is the probability that he or she studies on a weeknight?
0.6 = 60% that he or she studies on a weeknight.
