Answer:
[tex]{ \tt{p=\frac{3(x^{2} +1)}{2x-1}}} \\ { \tt{p(2x - 1) = 3( {x}^{2} + 1) }} \\ { \tt{2px - p = 3 {x}^{2} + 3 }} \\ { \tt{3 {x}^{2} - (2p)x + (p + 3) = 0}} [/tex]
By factorization :
[tex]{ \tt{ ( {p}^{2} - 3)( p + 3) \: is \: the \: zero}}[/tex]
Since the roots are real, they're greater than zero ( 0 < x ≤ +∞ ):
[tex]{ \tt{ ({p}^{2} - 3})(p + 3) \geqslant 0}[/tex]
