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What is the point-slope form of a line with slope 4/5that contains the point
(-2, 1)?
O A. y-1 = (x+2)
O B. y+1 = f(x-2)
O C. y+1 = $(x+2)
O D. y-1 = (x-2)

Respuesta :

Lanuel

Answer:

y - 1 = ⅘(x + 2)

Explanation:

Given the following data;

Points on the graph (x1, y1) = (-2, 1)

Slope, m = ⅘

To find the point-slope form of a line, we would use the formula;

y - y1 = m(x - x1)

Substituting into the formula, we have;

y - 1 = ⅘(x - (-2))

y - 1 = ⅘(x + 2)

y - 1 = ⅘x + 8/5

y = ⅘x + 8/5 - 1

y = ⅘x + 3/5

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