Answer:
The lengths of the sides are 6, 8 and 10.
Step-by-step explanation:
The vertices of a right angles triangle are E (2,2), F (2,8), and G (10,8)
The distance between the two points is
[tex]d=\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}[/tex]
So, the lengths of the sides are
[tex]EF=\sqrt{(8-2)^2+(2-2)^2} = 6 \\\\FG=\sqrt{(8-8)^2+(10-2)^2} = 8 \\\\GE=\sqrt{(8-2)^2+(10-2)^2} = 10 \\[/tex]
