Answer:
we arrive at the conclusion that the new employee installs the vertical blinds faster on average.
Step-by-step explanation:
null hypothesis; m₁-m₂ =0
alternative hypothesis; m₁-m₂<0
Given the information in this question, we first have to solve for the t statistic
[tex]t=\frac{22-24.8}{\sqrt{\frac{0.90^{2} }{10}+\frac{0.75^{2} }{10} } }[/tex]
[tex]t=\frac{-2.6}{\sqrt{o.081+0.05625} }[/tex]
[tex]t=\frac{-2.6}{0.37047}[/tex]
t = -7.018
the degree of freedom = n₁+n₂-2
= 10+10-2
= 18
Alpha α = 0.05
from these results the t critical value = -1.734
because the test statistic -7.018 < -1.734,
at 0.05 level of testing, we arrive at the conclusion that the new employee installs the vertical blinds faster on average than the veteran.
