In the right angle triangle ABC, the value of sin B is √21 / 5
How to use trigonometric ratios in a right angle triangle?
∠C = 90 degrees
Therefore,
cos A = √21 / 5
cos A = adjacent / hypotenuse
Therefore,
sin B = opposite / hypotenuse
using trigonometric ration,
opposite side = √21
hypotenuse = 5
Hence,
sin B = √21 / 5
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