Answer:
Equation = (x - 6 )² + ( y + 3 )² = 9
Step-by-step explanation:
The circle passes through ( 6, 0) and ( 6 , -6)
They are the coordinates of the diameter.
Using this we can find the centre of the circle.
Find the centre of the circle.
Centre of the circle is the mid- point of (6, 0) and ( 6, -6)
[tex]Centre = (\frac{x_1+x_2}{2} , \frac{y_1 + y_2}{2})[/tex]
[tex]=(\frac{6 + 6}{2}, \frac{0 + (-6)}{2})\\\\=(6, -3)[/tex]
Find the radius of the circle.
[tex]Radius = \frac{Diameter }{2}[/tex]
Diameter is the distance between the points (6 , 0) and ( 6, - 6)
[tex]Diameter = \sqrt{(x_2 - x_1)^2+ (y_2 - y_1)^2\\}[/tex]
[tex]=\sqrt{(6-6)^2 + (-6 -0)^2}\\\\=\sqrt{0 + 36} \\\\= 6[/tex]
Therefore,
[tex]Radius ,r = \frac{6}{2} = 3[/tex]
Standard equation of a circle:
[tex](x - a)^2 + (y - b)^2 = r^2 \ where \ (a , b) \ is \ the\ centre \ coordinates.[/tex]
Therefore , equation of the circle ;
[tex](x - 6)^2 + (y + 3)^2 = 3^2\\\\(x -6)^2 + (y + 3)^2 = 9[/tex]
