Answer:
The probability is 1/12.
Step-by-step explanation:
Number of elements in sample space is 6 . Even numbers are 2, 4 and 6 so the there are 3 three even numbers.
So, the probability of getting 3 on the first chance and then an even number in the second chance is
[tex]P = \frac{1}{6}\times \frac{3}{6}\\\\P = \frac{1}{12}[/tex]
