Answer:The distance from the school to the theater = 18 units
Step-by-step explanation:
Distance between (a,b) and (c,d) = [tex]\sqrt{(d-b)^2+(c-a)^2}[/tex] units.
Given: On a map of a town a school is located (-6, 3) and a movie theater is located (-6, -15).
So, distance between (-6, 3) and(-6, -15) = [tex]\sqrt{(-6-(-6))^2+(-15-3)^2}[/tex]
[tex]=\sqrt{0^2+(-18)^2}\\\\=\sqrt{18^2}\\\\=18\ units[/tex]
Hence, the distance from the school to the theater = 18 units
