Two particles, with identical positive charges and a separation of 2.65 10-2 m, are released from rest. Immediately after the release, particle 1 has an acceleration 1 whose magnitude is 5.00 103 m/s2, while particle 2 has an acceleration 2 whose magnitude is 7.70 103 m/s2. Particle 1 has a mass of 6.20 10-6 kg. (a) Find the charge on each particle. q1 = C q2 = C (b) Find the mass of particle 2. kg

Respuesta :

Answer:

a)  [tex]q=4.92*10^{-8} C[/tex]

b)  [tex]m=4.026*10^{-6} kg[/tex]

Explanation:

From the question we are told that:

Separation distance [tex]d=2.65*10^{-2} m[/tex]

Acceleration 1 [tex]a_1=5.00*10^3 m/s^2,[/tex]

Acceleration 2 [tex]a_2=7.70*10^3 m/s^2,[/tex]

Mass 1 [tex]m_1=6.20*10^{-6}[/tex]

Generally the equation for Force is mathematically given by

 [tex]F=ma[/tex]

For Particle 1

 [tex]F=6.2*10^{-6} *5*10^3[/tex]

 [tex]F=0.031 N[/tex]

Also

 [tex]F=\frac{kq_1*q2}{r^2}[/tex]

Where

 [tex]q_1=q_2[/tex]

Therefore

 [tex]0.031=\frac{9*10^9*q^2}{(2.65*10^-2)^2}[/tex]

 [tex]q=4.92*10^{-8} C[/tex]

b)

Generally the equation for Force is mathematically given by

 [tex]F=ma[/tex]

 [tex]0.031=7.7*10^3[/tex]

 [tex]m=4.026*10^{-6} kg[/tex]