A car accelerates along a straight road from rest to 90 km/h in 5.0 s. A) Find the magnitude of its average acceleration. B) Find the velocity of the car at t = 1.0 s, t = 2.0 s and t = 5.0

Respuesta :

Answer:

a)   [tex]A=5m/s^2[/tex]

b)   [tex]V=25m/s[/tex]

Explanation:

From the question we are told that:

Velocity [tex]v=90km/h=25m/s[/tex]

Time [tex]t=5.0s[/tex]

a)

Generally From Newton's motion equation for Average acceleration is   mathematically given by

  [tex]A=\frac{V-U}{t}[/tex]

Since its from Rest Therefore

  [tex]U=0[/tex]

 [tex]A=\frac{25m/s-0}{5s}[/tex]

 [tex]A=5m/s^2[/tex]

b)

Generally the equation for Average Velocity is mathematically given by

  [tex]V=u+at[/tex]

 [tex]AT t=1.0s\\\\V=0+5(1)[/tex]

 [tex]V=5m/s[/tex]

 [tex]AT t=2.0s\\\\V=0+5(2)[/tex]

 [tex]V=10m/s[/tex]

 [tex]AT t=5.0s\\\\V=0+5(5)[/tex]

 [tex]V=25m/s[/tex]