Answer:
The passenger's luggage has an excess weight of 2 kg, which is 10% of the maximum weight.
Step-by-step explanation:
First, we need to find the weight (W) of the 4 bags:
[tex] W = 3.5 kg + 15 kg + 2 kg + 1.5 kg = 22 kg [/tex]
Now, knowing that the maximum allowed (M) is 20 kg the excess weight of the luggage is:
[tex] W_{e} = W - M = 22 kg - 20 kg = 2 kg [/tex]
We can express the excess weight in percentage as follows:
[tex] \% W_{e} = \frac{W_{e}}{M} \times 100 = \frac{2 kg}{20 kg}\times 100 = 10 \% [/tex]
Therefore, the passenger's luggage has an excess weight of 2 kg, which is 10% of the maximum weight.
I hope it helps you!
