Find the hypotenuse, c, of the triangle.

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Work Shown:
a^2+b^2 = c^2 ... pythagorean theorem
c = sqrt(a^2+b^2)
c = sqrt(4^2+12^2)
c = 12.6491106406736
c = 12.65
Answer:
Step-by-step explanation:
Given,
Height of the triangle = 4
Base of the triangle = 12
Therefore,
Hypotenuse of the triangle
[tex] {(base)}^{2} + {(height)}^{2} = {(hypotenuse)}^{2} [/tex]
[tex] = > {(12)}^{2} + {(4)}^{2} = {(hypotenuse)}^{2} [/tex]
[tex] = > {(hypotenuse)}^{2} = 144 + 16[/tex]
[tex] = > {(hypotenuse)}^{2} = 160[/tex]
[tex] = > hypotenuse = \sqrt{160} [/tex]
[tex] = > hupotenuse = \sqrt{5 \times 2 \times 2 \times 2 \times 2 \times 2} [/tex]
[tex] = > hypotenuse = 2 \times 2 \sqrt{5 \times 2} [/tex]
[tex] = > hypotenuse = 4 \sqrt{10} \: (ans)[/tex]