Answer:
[tex]{ \boxed{ \tt{ formular : { \tt{area}} = \pi {r}^{2}}}} \\ { \green{radius = \frac{diameter}{2} = \frac{12}{2}}} \\ area = \frac{22}{7} \times { (\frac{12}{2} )}^{2} \\ { \boxed{area = 113.04 \: {ft}^{2} }} \\ \\ { \underline{ \blue{ \tt{becker \: jnr}}}}[/tex]
