Answer:
[tex]{ \boxed{ \bf {general \: equation : y = mx + c}}} \\ m \: is \: the \: slope \\ { \green{slope = \frac{ \triangle \: y}{ \triangle \: x} }} \\ m = \frac{(4 - 5)}{(3 - ( - 2))} \\ m = - \frac{1}{5} \\ \therefore \: { \red{y = - \frac{1}{5} x + c}} \\ consinder \: the \: first \: point : \\ 5 = ( - \frac{1}{5} \times - 2) + c \\ c = \frac{23}{5} \\ \therefore \: { \boxed{ \bf{answer : 5y = - x + 23}}} \\ \\ { \underline{ \blue{ \tt{becker \: jnr}}}}[/tex]
