due in 30 mins help plssss

Answer:
x = [tex]7\sqrt{2}[/tex]
Step-by-step explanation:
a is the hypotenuse of the right angled triangle ehereas the other two sides are legs of a right angle triangle .
since the other two sides are equal both should be denoted as x.
now the value of a is given i.e 14 m
using pythagoras theorem,
pythagoras theorem states that sum of square of two smaller sides of a right triangle is equal to the sum of square of hypotenuse. so,
a^2 + b^2 = c^2
x^2 + x^2 = 14^2
2x^2 = 196
x^2 = 196/2
x^2 = 98
x = [tex]\sqrt{98}[/tex]
x = [tex]7\sqrt{2}[/tex]
Answer:
[tex]x=7\sqrt{2}[/tex]
Step-by-step explanation:
The given triangle is a right isosceles triangle. This means that it is a triangle with two congruent sides and a right angle (indicated by the box around one of the angles). One of the properties of a right isosceles triangle is that it follows the following sides-ratio,
[tex]x-x-x\sqrt{2}[/tex]
Where (x) represents the legs (sides adjacent to the right angle of a right triangle) or the congruent sides in this case. ([tex]x\sqrt{2}[/tex]) represents the hypotenuse or the side opposite the right angle. Form a proportion based on the given information and solve for the unknown value (x).
[tex]x=\frac{a}{\sqrt{2}}[/tex]
Substitute,
[tex]x=\frac{14}{\sqrt{2}}[/tex]
Simplify,
[tex]x=\frac{14}{\sqrt{2}}\\\\x=\frac{14*\sqrt{2}}{\sqrt{2}*\sqrt{2}}[/tex]
[tex]x=\frac{14\sqrt{2}}{2}[/tex]
[tex]x=7\sqrt{2}[/tex]