Respuesta :

thpmgshristi
Here,
n(X)=200
n(Y)=300
n(XuY)=400
n(XnY)=?
Now,
n(XnY)=n(X)+n(Y)-n(XuY)
=200+300-400
=500-400
=100
n(XnY)=100
Hdhsksjsuedjejdjejdndhdnddhmd

Otras preguntas