Answer:
Option C is the correct one
Step-by-step explanation:
given equation of a line is y=-1/3x+1
comparing the given equation with y=mx+c
therefore,slope(m)=-1/3
then,
slope of line perpendicular to the line having slope -1/3 is (m2)=3
Equation of line having slope (m2)=3 and passing through point (2,7) is
y-y1=m2*(x-x1)
or,y-7=3(x-2)
or,y-7=3x-6
or,3x-y-6+7=0
or,3x-y+1=0
or,3x-y=-1 is the req.equation.
