Answer:
y=3/5x+1
Step-by-step explanation:
Hi there!
We are given the equation -3x+5y=-8 and we want to find the equation of the line that is parallel to -3x+5y=-8 and contains the point (-15,-8)
parallel lines have the same slopes, but different y intercepts.
So let's first find the slope of -3x+5y=-8
We can do this by converting the equation from standard form (ax+by=c where a, b, and c are free coefficients (numbers)) to slope-intercept form (y=mx+b, where m is the slope and b is the y intercept)
add 3x to both sides
5y=3x-8
divide by 5 on both sides
y=3/5x-8/5
3/5 is in the place of where m is, so that means that 3/5 is the slope of the line
we can write the equation of the new line in slope-intercept form.
Here it is so far:
y=3/5x+b
we need to find b
Because the line will pass through the point (-15,-8), we can use it to solve for b
substitute -15 as x and -8 as y
-8=3/5(-15)+b
multiply
-8=-9+b
add 9 to both sides
1=b
substitute 1 as b into the equation
y=3/5x+1
There's the equation of the line :)
Hope this helps!
