Answer:
[tex]-\frac{3}{x} + \frac{7y}{x} = \frac{-3+ 7y}{x}[/tex]
Step-by-step explanation:
Given
[tex]-\frac{3}{x} , \frac{7y}{x}[/tex]
Required
Add
The statement can be interpreted as:
[tex]-\frac{3}{x} + \frac{7y}{x}[/tex]
Take LCM
[tex]-\frac{3}{x} + \frac{7y}{x} = \frac{-3+ 7y}{x}[/tex]
