Answer:
[tex]3x^{4}[/tex]
Step-by-step explanation:
multiply
9 times 3 is 27
x to the fourth times x to the eighth is x to the twelfth
this all under the cube root so [tex]\sqrt{27x^{12} }[/tex] I know that is the square root but pretend that it is the cube root of it
The cube root of 27 is 3 and the cube root of x to the twelfth is x to the fourth
so you have 3 times x to the fourth or [tex]3x^{4}[/tex]
