Answer:
The velocity of muons is [tex]8.1\times 10^{7}m/s[/tex].
Explanation:
Electric field, E = [tex]3.4\times 10^{6} V/m[/tex]
Magnetic field, B = 42 mT = 0.042 T
mass, m =207 x mass of electron
charge, q = [tex]1.6\times 10^{-19}C[/tex]
Let the velocity is v.
The magnetic force on the charge is balanced by the electric force.
q v B sin 90 = q E
v x B = E
v x 0.042 = [tex]3.4\times 10^6[/tex]
v = [tex]8.1\times 10^{7}m/s[/tex]
