Answer:
[tex]n=1.3\times 10^{12}[/tex]
Step-by-step explanation:
Given that,
The radius of a cell, r = 10⁻³ cm
The density of the cell, d = 1.1 g/cm³
The weight of the Koala, m = 6 kg = 6000 grams
The density of an object is given by:
[tex]d=\dfrac{m}{V}[/tex]
For n cells,
[tex]nd=\dfrac{m}{V}\\\\n=\dfrac{m}{dV}[/tex]
Put all the values,
[tex]n=\frac{6000}{\frac{4}{3}\cdot\pi\cdot\left(10^{-3}\right)^{3}\cdot1.1}\\\\n=1.3\times 10^{12}[/tex]
So, there are [tex]1.3\times 10^{12}[/tex]cells in the average koala.
