23. A mass of water dropped in temperature by 25.1°C. It gave off 5240.0 J of energy in the process. Approximately how many grams of water were involved? A. 40g. B. 45g. C. 50g. D. 55g.

Heat energy is the product of the mass, specific heat, and the change in the temperature. 50 gm of water was involved in the reaction that gave 5240.0 J of energy.

What is specific heat?

Specific heat is the heat required by one gram of the substance to have an increase in the temperature by one Celsius degree.

Given,

Change in temperature (ΔT) = 25 °C

Q = 5240 J

Specific heat of water (Cp) = 4.2 J/g°C

The heat released = m x Cp x ΔT

5240 = m x 4.2 x 25.1

m = 5240 ÷ 105.42

m = 49.7 gm ≈ 50 g

Therefore, 50 gm is the mass of water involved.

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