contestada

find the angles, θ<0<360, that satisfy the equation below, to the nearest 10th of a degree.

sin(θ)= -√11/5

Respuesta :

Answer:

[tex] \sin( \theta) = - \frac{ \sqrt{11} }{5} \\ \theta = \sin {}^{ - 1} ( - \frac{ \sqrt{11} }{5} ) \\ \theta = 41.6 \degree, \: 221.6 \degree, \: 318.4 \degree[/tex]

Otras preguntas