Respuesta :

Answer:

[tex] \frac{(49 {t}^{ - 5} )}{( {7}^{ - 3} \times 10 {e}^{ - 9} ) \times (t \times 0)} \\ = \frac{( { {7}^{2} t}^{ - 5} ) \times 7 {}^{3} }{(10 {e}^{ - 9} )} \\ = \frac{ {7}^{5} }{( 10{t}^{5} {e}^{ - 9} ) } [/tex]