A 50 foot ladder is set against the side of a house so that it reaches up 48 feet. If Mila grabs the ladder at its base and pulls it 6 feet farther from the house, how far up the side of the house will the ladder reach now? (The answer is not 42 ft.) Round to the nearest tenth of a foot.

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cnfkcz5ccg cnfkcz5ccg · Answer 1 · 2021-05-15T02:23:32+02:00

Answer: ~31.3

first use the pythagorean theorem. a^2+(40)^2=50^2.

simply. a+1600=2500. subtract 1600 from both sides. a^2=900.

square root both sides to get a= 30

then find how far the top of the ladder is from the ground once in its new position.

a^2+(39)^2=50^2.

simplify. a^2+1512=2500. subtract 1512 from both sides to get a^2=979.

square root both sides to get a=31.288975. round to the nearest tenth to get a=31.3

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arynjohnson2018 arynjohnson2018 · Answer 2 · 2021-10-21T07:41:13+02:00

Answer: 45.8

Step-by-step explanation:

1. Find how far the bottom of the ladder is from the bottom of the house:

(use pythagorean theorem)

(48)2 (50)2

a2 + 2304 = 2500

-2304 -2304

a2= 196

square root 196 = 14 ( ignore negative root, the length must be positive)

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Then find how far the top of the ladder is from the ground once it is put in its new position:

(20)2 (50)2

a2 + 400 = 2500

-400 -400

a2 = 2100

square root 2100

a = 45.825756

a ≈ 45.8 (round to the nearest tenth)