A jar contains 6 red marbles, 3 green marbles, 5 white marbles, and 7 yellow marbles. Find the probability of drawing a green marble. All answers should be given as a fraction in simplest form!
Any help is appreciated! Thanks!

since its asking for the probability of "a" marble, and not all the green marbles, you add everything up and slap what outcome (1 in this case) on top of the 21

here is cat

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mayeee03 mayeee03 · Answer 2 · 2021-05-15T02:04:47+02:00

mayeee03 mayeee03

15-05-2021

Answer:

3 is for green marbles

21 is the total of all marbles

Step-by-step explanation:

you only have 1 event so I think we don't need some formula or something

the formula is this if the event A and B has no intersection P( A U B)= P(A)+P(B)

and if it has intersection, the formula is like this P( A ∩ B)=P(A)+P(B)-P( A ∩ B)

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A jar contains 6 red marbles, 3 green marbles, 5 white marbles, and 7 yellow marbles. Find the probability of drawing a green marble. All answers should be given as a fraction in simplest form! Any help is appreciated! Thanks!

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A jar contains 6 red marbles, 3 green marbles, 5 white marbles, and 7 yellow marbles. Find the probability of drawing a green marble. All answers should be given as a fraction in simplest form!
Any help is appreciated! Thanks!